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Old 12-01-2006, 09:02 AM   #76 (permalink)
 
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Re: Riddle

Quote:
Originally Posted by Karkianman101 View Post
I think in this case movement does not include rotation. If someone takes out a diagonal line, then its pair is assumed to straighten itself.
Why assume that? Buck already told us that "IX + II = 11" is not the answer. That's a case where we took half of the 'V' and moved it somewhere, and rotated the other half to make it verticle. This appears to give us reason to think we shouldn't assume that.
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Old 12-01-2006, 09:22 AM   #77 (permalink)
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Re: Riddle

Quote:
Originally Posted by Buck Fush View Post
This statement:

IX + VI = 11

can be made true by moving one and only one line from one place in the expression to another.

Is this the solution:

X + vT = 11

i.e X + squareroot(1) = 11 , moving the initial 'I' to above the final 'I'
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Old 12-01-2006, 12:06 PM   #78 (permalink)
 
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Re: Riddle

Late to the party again...

IX - -VI = 11

where the right hand side is Base 14 (you never specified what base it was in)

9 - (-6) = 15
and
11 base 14 = 15

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Old 12-01-2006, 12:46 PM   #79 (permalink)
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Re: Riddle

Ok, I don't know if the solution I posted above is the solution, but if it is, here's another puzzle to keep y'all going:

You have 9 indistinguishable coins. One of them is slightly heavier than the others, but no test you can do will reveal which one it is. The only tool that can do so is a set of scales which you have. (i.e. the old school style where you put some stuff on one side, some other stuff on the other and it tells you which one is heavier)

How can you discover which is the heavier coin by only using the scales twice?

(If you've heard this before, please don't give the answer right away.)
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Old 12-01-2006, 01:15 PM   #80 (permalink)
 
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Re: Riddle

place 3 coins on each side.

if equal then one of the left over coins is heavier, place one of the left over coins on each side.... if equal then remaining coin is heavier.

if one side is heavier on the original use, then place one coin from that side on each side of the scale. if equal, then the left out coin is heavier.
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Old 12-01-2006, 01:38 PM   #81 (permalink)
 
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Re: Riddle

Quote:
Originally Posted by sordavie View Post
But, you have access to other people's answers, and the original poster has updated the rules.



Your sentence is something like this 'IX + II = X1' and 'X1' does not equal "11" for the very same reason '11I' or 'I11' or '1I1' does not equal "3."



Also, if you're careful, you'll notice that you haven't followed directions. It says move one and only one line. You have moved two. I don't see why straightening out the '1' on the right hand side of the '=' to make one slash of the 'X' doesn't count as having moved a line. Rotation is movement. Rotating a line counts as movement. So, you've made the rotation of that line, and you've moved a line from the 'V' over to the other side of '='. That's two lines moved, not one and only one line moved.
Quote:
Originally Posted by Karkianman101 View Post
I think in this case movement does not include rotation. If someone takes out a diagonal line, then its pair is assumed to straighten itself.

Sordavie is right. (And thanks for that, you saved me a lot of typing.) Rotation IS movement. (Although it is acceptable to rotate the line you're moving if you think it's necessary.)

I'm going to make this easier by saying that the result will not only be equality, but it will actually equal "11". I put that in quotes to make it literal. It will be "one one", no tricks there. The line will be moved from some place on the left side of the equation to another place on the left side of the equation.

I'll give another hint next Friday.
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Old 12-01-2006, 01:43 PM   #82 (permalink)



 
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Re: Riddle

wait, this isn't it?

Quote:
Originally Posted by Ale View Post
Is this the solution:

X + vT = 11

i.e X + squareroot(1) = 11 , moving the initial 'I' to above the final 'I'
it's bloody brilliant and SHOULD be the answer if it's not!!
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Old 12-01-2006, 02:16 PM   #83 (permalink)
 
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Re: Riddle

Quote:
Originally Posted by Ale View Post
Is this the solution:

X + vT = 11

i.e X + squareroot(1) = 11 , moving the initial 'I' to above the final 'I'
Quote:
Originally Posted by WhiskeySix View Post
wait, this isn't it?



it's bloody brilliant and SHOULD be the answer if it's not!!
Don't know how I missed that. We have a winner!!!
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Old 12-06-2006, 01:14 PM   #84 (permalink)
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Re: Riddle

Quote:
Originally Posted by Buck Fush View Post
We have a winner!!!
Sweet.

Ddog already got my follow up puzzle, so it's up to him if this thread'll continue.
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Old 12-06-2006, 06:50 PM   #85 (permalink)
 
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Re: Riddle

I can't believe more people haven't commented on the answer after it took so long to find it.
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Old 12-06-2006, 07:26 PM   #86 (permalink)
 
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Re: Riddle

I like my answer better.

I thought of this but decided it wasn't elegant enough to try. In order to get the square root sign, the top of the 'I' will hit the '-'. But, that looks messy. If the top of the I doesn't hit the '-', then the '-' doesn't hit the top of the 'V' and that looks messy. The symbol 'VT' where the top of the 'V' touches the top of the 'T' isn't the square root of one. That's some other symbol that has no common use yet. The square root of one is a combination of two seperate symbols--the square root symbol and the symbol for one. There's none of that sort of mess with my solution. Oh well.
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Old 12-06-2006, 07:28 PM   #87 (permalink)


 
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Re: Riddle

Quote:
Originally Posted by Buck Fush View Post
I can't believe more people haven't commented on the answer after it took so long to find it.
There were better answers...
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Old 12-06-2006, 07:39 PM   #88 (permalink)
 
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Re: Riddle

Do it with tooth picks and it'll look better. The reason for the vT is that it's imposssible to do the squareroot symbol without a graphic.

Quote:
Originally Posted by sordavie View Post
I like my answer better.

I thought of this but decided it wasn't elegant enough to try. In order to get the square root sign, the top of the 'I' will hit the '-'. But, that looks messy. If the top of the I doesn't hit the '-', then the '-' doesn't hit the top of the 'V' and that looks messy. The symbol 'VT' where the top of the 'V' touches the top of the 'T' isn't the square root of one. That's some other symbol that has no common use yet. The square root of one is a combination of two seperate symbols--the square root symbol and the symbol for one. There's none of that sort of mess with my solution. Oh well.
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Old 01-31-2007, 12:39 PM   #89 (permalink)
 
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Re: Riddle

We need another riddle...
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Old 02-03-2007, 06:45 PM   #90 (permalink)


 
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Re: Riddle

What's red and green and goes a hundred miles an hour?
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